A wheel of radius $1 m$ rolls forward half a revolution on a horizontal ground. The magnitude of the displacement of the point of the wheel initially in contact with the ground is then:

2 π

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\sqrt{2} π

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\sqrt{x^{2} + 4}

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π

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Solution

The correct option is A $2 π$

Circumference= $2 π (1) = 2 π$

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Given that $P$ is a point on a wheel rolling on a horizontal ground. The radius of the wheel is $R$ . Initially if the point $P$ is in contact with the ground, the wheel rolls through half revolution. What is the displacement of point $P$ ?

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A wheel of radius 1m rolls forward half a revolution on a horizontal ground. The magnitude of the displacement of the point of the wheel initially in contact with the ground is then:

The correct option is A 2πCircumference=2π(1)=2π

A wheel of radius $1 m$ rolls forward half a revolution on a horizontal ground. The magnitude of the displacement of the point of the wheel initially in contact with the ground is then:

The correct option is A $2 π$

Circumference= $2 π (1) = 2 π$