A wheel of radius 30 cm is connected to a rod of length 150 cm- The wheel starts to rotate at -2 rad - sec on a circular track- Find rate of turning of the rod-A- 0-4 rad - secB- 0-6 rad - secC- 0-8 rad - secD- 0-2 rad - sec

The correct option is A 0.4 rad/secv_c = r ω nbsp; (No slipping) = 0.3 × 2 = 0.6 m/s ω' = nbsp; v_c/l nbsp; (for circular motion) = 0.6/1.5 = 6/15 = 2/5 ...

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Standard XII

Physics

Uniform Circular Motion

A wheel of ra...

Question

A wheel of radius 30 cm is connected to a rod of length 150 cm. The wheel starts to rotate at $ω$ = 2 rad/sec on a circular track. Find rate of turning of the rod.

0.4 rad/sec

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0.6 rad/sec

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0.8 rad/sec

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0.2 rad/sec

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Solution

The correct option is A 0.4 rad/sec
$v_{c} = r ω$ (No slipping)
$= 0.3 \times 2$
$= 0.6 m / s$
$ω^{'} = \frac{v_{c}}{l}$ (for circular motion)
$= \frac{0.6}{1.5} = \frac{6}{15} = \frac{2}{5}$ rad/sec.

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A wheel of radius 30 cm is connected to a rod of length 150 cm. The wheel starts to rotate at ω = 2 rad/sec on a circular track. Find rate of turning of the rod.

The correct option is A 0.4 rad/secvc=rω (No slipping) =0.3×2 =0.6m/s ω′=vcl (for circular motion) =0.61.5=615=25 rad/sec.

A wheel of radius 30 cm is connected to a rod of length 150 cm. The wheel starts to rotate at $ω$ = 2 rad/sec on a circular track. Find rate of turning of the rod.

The correct option is A 0.4 rad/sec
$v_{c} = r ω$ (No slipping)
$= 0.3 \times 2$
$= 0.6 m / s$
$ω^{'} = \frac{v_{c}}{l}$ (for circular motion)
$= \frac{0.6}{1.5} = \frac{6}{15} = \frac{2}{5}$ rad/sec.