A wheel rotates with a constant acceleration of $2 r a d s^{- 2}$ . If the wheel starts from rest, how many revolution will it make in the first $10$ seconds?

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Solution

The correct option is C 16
If $θ$ be the angular displacement, then $θ = \frac{1}{2} α t^{2} = 0.5 (2) (10)^{2} = 100$ radians (using equation : $S = u t + 1 / 2 a t^{2}$ )
Thus, number of revolutions $= \frac{θ}{2 π} = \frac{100}{2 π} = 15.92 \sim 16$

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A wheel rotates with a constant acceleration of 2 rads−2. If the wheel starts from rest, how many revolution will it make in the first 10 seconds?

The correct option is C 16If θ be the angular displacement, then θ=12αt2=0.5(2)(10)2=100 radians (using equation : S=ut+1/2at2)Thus, number of revolutions =θ2π=1002π=15.92∼16

A wheel rotates with a constant acceleration of $2 r a d s^{- 2}$ . If the wheel starts from rest, how many revolution will it make in the first $10$ seconds?

The correct option is C 16
If $θ$ be the angular displacement, then $θ = \frac{1}{2} α t^{2} = 0.5 (2) (10)^{2} = 100$ radians (using equation : $S = u t + 1 / 2 a t^{2}$ )
Thus, number of revolutions $= \frac{θ}{2 π} = \frac{100}{2 π} = 15.92 \sim 16$