A wheel rotates with a constant angular acceleration of 3.6rad/s2. If angular velocity of the wheel is 4.0rad/s at time t0=0, what angle does the wheel rotate in 1s? What will be its angular velocity at t=1s?
A
θ=5.8rad,ω=0.4rad/s
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B
θ=2.2rad,ω=0.4rad/s
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C
θ=5.8rad,ω=7.6rad/s
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D
θ=2.2rad,ω=7.6rad/s
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Solution
The correct option is Cθ=5.8rad,ω=7.6rad/s Given,
Angular acceleration α=3.6rad/s2
Angular velocity of wheel at t0=0,ω0=4.0rad/s
Angle rotated in 1 second from eq. θ=ω0t+12αt2 θ=4(rad/s)×1(s)+12×(3.6rad/s2)×1×(s)2 θ=5.8rad
From eqn. ω=ω0+αt, angular velocity at t=1s ω=4(rad/s)+3.6(rad/s2)×1(s) ω=7.6rad/s