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Question

# A whistle emitting a sound of frequency 440 Hz is tied to a string of 1.5 m length and rotated with an angular velocity of 20 rad/s in the horizontal plane. Then the range of frequencies heard by an observer stationed at a large distance from the whistle will be (v = 330 m/s)

A
400.0 Hz to 484.0 Hz
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B
403.3 Hz to 480.0 Hz
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C
400.0 Hz to 480.0 Hz
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D
403.3 Hz to 484.0 Hz
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Solution

## The correct option is D 403.3 Hz to 484.0 HzFrequency heard by the observes will be maximum when the source is in position D. In this case, source will be approaching towards the stationary observer, almost along the line of sight (as observer is stationed at a larger distance). nmax=vv−vsn=330×440330−1.5×20=484Hz Similarly, frequency heard by the observer will be minimum when the source reaches at position B. now, the source will be moving away from the observer. nmax=vv+vs×n=330330+1.5×20×440=330×440360=403.3Hz

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