wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A whistle revolves in a circle with a constant angular speed of 20 rad/s connected with a string of length 50 cm. If the frequency of the sound from the whistle is 385 Hz, then what is the minimum frequency heard by an observer at rest who is far away from the centre?
(velocity of sound is 370 m/s)

A
385 Hz
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
375 Hz
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
394 Hz
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
333 Hz
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 375 Hz
Given:
Angular speed of the whistle, ω=20 rad/s
Radius of the circle, r=50 cm=0.5 m
Frequency of sound from the whistle, f=385 Hz
Velocity of sound, v=370 m/s

The line joining the source and the observer will be a secant passing through the centre.

Frequency heard by observer will be minimum when the source recedes away from him as shown in above figure.
Speed of the source,
vs=rω=0.5×20=10 m/s
Now, frequency heard by the observer,
fmin=f0(vv+vs)
fmin=385×(370370+10)
fmin=375 Hz

flag
Suggest Corrections
thumbs-up
18
Join BYJU'S Learning Program
Join BYJU'S Learning Program
CrossIcon