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Standard XII

Chemistry

Preparations and Uses of Sodium Carbonate

A white cryst...

Question

A white crystalline solid 'A' on boiling with caustic soda solution gives a gas 'B', which on passing through an alkaline solution of potassium tetraiodomercurate (II) solution gives a brown ppt. The substance 'A' on heating evolves a neutral gas 'C', which is inert at room temperature and reactive in presence of the catalyst and does not give brown fumes with nitric oxide.

The substance 'A' is___________.

N H_{4} C l

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N H_{4} N O_{3}

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N H_{4} N O_{2}

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N a N O_{3}

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Solution

The correct option is C $N H_{4} N O_{2}$

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Similar questions

Q. A white crystalline solid

A

on boiling with caustic soda solution gave a gas

B

which when passed through an alkaline solution of potassium mercuric iodide gave a brown ppt. The substance

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on heating gave a gas

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which rekindled a glowing splinter but did not give brown fumes with nitric oxide. The gas

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solution. The filtrate gives a black precipitate (C) when

H_{2} S

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N a I

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H C l

but liberates reddish brown gas on heating.

Compound (A) is _________.

When a white crystalline compound X is heated with

K_{2} C r_{2} O_{7}

and concentrated

H_{2} S O_{4}

, a reddish brown gas A is evolved. On passing A into caustic soda solution, a yellow-colored solution B is obtained. Neutralizing the solution of B with acetic acid and on subsequent addition of lead acetate, a yellow precipitate C is obtained. When X is heated with

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H C l

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Q. An aqueous solution of salt (A) gives a white crystalline precipitate (B) with NaCl solution. The filtrate gives a black precipitate (C) when

H_{2} S

is passed through it. Compound (B) dissolves in hot water and the solution gives yellow precipitate (D) on treatment with potassium iodine and on cooling. The compound (A) does not give any gas with dilute HCl but liberates a reddish brown gas on heating. Compounds (A) to (D) are identified as:

(A) :

P b (N O_{3})_{3}

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P b C l_{2}

P b S

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P b I_{2}

If true enter 1, else enter 0.

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The correct option is C NH4NO2

The correct option is C $N H_{4} N O_{2}$