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Magnetic Properties

A white cryst...

Question

A white crystalline substance dissolves in water. On passing $H_{2} S$ in this solution, a black precipitate is obtained. The black precipitate dissolves completely in hot $H N O_{3}$ . On adding few drops of concentrated $H_{2} S O_{4}$ , a white precipitate is obtained which is soluble in ammonium acetate. The white precipitate is that of

A

B a S O_{4}

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B

S r S O_{4}

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C

P b S O_{4}

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D

A g_{2} S O_{4}

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Solution

The correct option is D $P b S O_{4}$
$P b^{2 +} + H_{2} S a c i d i c - -- \to P b S (B l a c k p p t .) ↓ + H_{2} O ↑$

$3 P b S + 8 H N O_{3} \to 3 P b (N O_{3})_{2} + 2 N O + 3 S + 4 H_{2} O$

$3 P b (N O_{3})_{2} + H_{2} S O_{4} \to P b S O_{4} (w h i t e p p t .) ↓ + 2 H N O_{3} (a q)$

$P b S O_{4} + 2 C H_{3} C O O N H_{4} \to (C H_{3} C O O)_{2} P b + (N H_{4})_{2} S O_{4}$

$B a S$ and $S r S$ precipitates are not black in colour. $A g_{2} S O_{4}$ is white precipitate but does not dissolve in ammonium acetate.

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