A white object AB is kept before a convex lens. The lens produces the images of white object AB with sizes as $B_{v} A_{v}$ and $B_{r} A_{r}$ with respect to violet and red colours. Then :

Size of

B_{v} A_{v} =

Size of

B_{r} A_{r}

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Size of

B_{v} A_{v}

> size of

B_{r} A_{r}

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Size of

B_{r} A_{r}

> size of

B_{v} A_{v}

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Size of

B_{r} A_{r} =

size of

\sqrt{B_{v} A_{v}}

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Solution

The correct option is C Size of $B_{r} A_{r}$ > size of $B_{v} A_{v}$
Red colour has wavelength greater than violet and we know that as wavelength increases, deviation gets decreased. So, $B_{r} A_{r}$ will be greater in size with respect to $B_{v} A_{v}$ .

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\frac{1}{n}

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