A white powder when strongly heated gives off brown, fumes. A solution of this powder gives a yellow precipitate with a solution of $K I$ . When a solution of barium chloride is added to a solution of powder, a white precipitate results. This white powder may be :

A soluble sulphate

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K B r

N a B r

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B a {(N O_{3})}_{2}

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A g N O_{3}

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Solution

The correct option is C $A g N O_{3}$
This white powder may be $B a {(N O_{3})}_{2}$ .

As the compound gives brown fumes, the anion is nitrate and compound reacts with $K I$ and barium chloride then the cation will be $A g^{+}$ .

$A g N O_{3} ⟶ A g + N O_{2} + \frac{1}{2} O_{2}$

$A g N O_{3} + K I ⟶ A g I + K N O_{3}$ ;

$B a C l_{2} + 2 A g N O_{3} ⟶ 2 A g C l + B a {(N O_{3})}_{2}$

So, the corret option is $D$

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A white powder when strongly heated gives off brown, fumes. A solution of this powder gives a yellow precipitate with a solution of KI. When a solution of barium chloride is added to a solution of powder, a white precipitate results. This white powder may be :

The correct option is C AgNO3This white powder may be Ba(NO3)2.As the compound gives brown fumes, the anion is nitrate and compound reacts with KI and barium chloride then the cation will be Ag+.AgNO3⟶Ag+NO2+12O2AgNO3+KI⟶AgI+KNO3;BaCl2+2AgNO3⟶2AgCl+Ba(NO3)2So, the corret option is D

A white powder when strongly heated gives off brown, fumes. A solution of this powder gives a yellow precipitate with a solution of $K I$ . When a solution of barium chloride is added to a solution of powder, a white precipitate results. This white powder may be :