A whole number is added to 49 and the same number is subtracted from 49. The sum of the resulting numbers is
A
0
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B
49
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C
50
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D
98
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Solution
The correct option is D98 Let the required whole number be x.
Resulting number when addedR1=49+x⋯(i)
Resulting number when subtractedR2=49−x⋯(ii)
Sum of resulting numbers =R1+R2(From (i),(ii)) =49+x+49−x=98 ∴Sum of resulting numbers is 98.