(a) Why are $M n_{+ 2}$ compounds more stable than $F e_{2 +}$ towards oxidation to their +3 state?
(b) $[T i (H_{2} 0)_{6}]^{3 +}$ gives violet coloured aqueous solution but $[M g (H_{2} 0)_{6}]^{2 +}$ solution is colourless, why?

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Solution

(a) ${M n}^{2 +} \Rightarrow {[A r]}^{18} {3 d}^{5}$
${F e}^{2 +} \Rightarrow {[A r]}^{18} {3 d}^{6}$ .
half filled and full-filled are more stable
$∴ {M n}^{2 +},$ being stable, shows resistance to oxidation to ${M n}^{3 +}$ . Also, ${F e}^{3 +}$ has $d^{6}$ configuration, thus by loosing one $e^{-}$ , it attains stable configuration.
$∴ {F e}^{2 +}$ easily gets oxidised to ${F e}^{3 +}$
(b) aq. solution of ${[T i {(H_{2} O)}_{6}]}^{3 +}$ absorb greenish yellow component of white light and that why d-d transition takes place and as a result aq. solution appears purple, ${b C}_{y}$ purple is compensatory colour of greenish yellow.

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