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B
a
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C
0
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D
None of these
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Solution
The correct option is C 0 Let a=a1ˆi+a2ˆj+a3ˆk Then, a.ˆi=a1,a.ˆj=a2,a.ˆk=a3 a׈i=−a2ˆk+a3ˆj.a׈j=a1ˆk−a3ˆi and a׈k=−a1ˆj+a2ˆi Therefore, (a.ˆi)(a׈i)+(a.ˆj)(a׈j)+(a.ˆk)(a׈k) =a1(−a2ˆk+a3ˆj)+a2(a1ˆk−a3ˆi)+a3(−a1ˆj+a2ˆi) =0