A window whose area is $2 m^{2}$ opens on street where the street noise result in an intensity level at the window of $60 d b$ . How much acoustic power enters the window via sound waves ? Now, if an acoustic absorber is fitted at the window?

8 μ W

No worries! We‘ve got your back. Try BYJU‘S free classes today!

10 μ W

No worries! We‘ve got your back. Try BYJU‘S free classes today!

4 μ W

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2 μ W

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D $2 μ W$
Intensity = 60 dB
60 = 10 log $(\frac{I}{I_{r e f}})$

where $I_{r e f}$ is the refrence intensity , general value of this is given by

$I_{r e f} = 10^{- 12} \frac{w a t t}{m^{2}}$

$\frac{I}{10^{- 12}}$ = anti log (6)

$I = 10^{- 12} \times a n t i l o g (6) = 10^{- 12} \times 10^{6} = 10^{- 6}$

Power = I $\times$ area = $2 \times 10^{- 6}$ watt

Suggest Corrections

Similar questions

A

window whose area is

2 m^{2}

opens on a street where the street noise result in an intensity level at the window of 60

d B

. Now, if an acoustic absorber of absorption coefficient 0.6 is fitted at the window, the energy will it collect from street in 5 hours is: (

I_{0} = 10^{- 6} W m^{- 2}

)

You live on a busy street, but as a music lover, you want to reduce the traffic noise. If you install special sound-reflecting windows that reduce the sound intensity level (in dB) by 30 dB, by what fraction have you lowered the sound intensity $(i n \frac{w}{m^{2}})$ ?

Q. Rahul is standing on the street and wants to throw an

8 k g

book up to his friend who is leaning out of a window

5 m

above street level. With what velocity Rahul must throw the book so that it reaches his friend in the window?

Q. A person on the street wants to throw an 8 kg book up to a person leaning out of a window 5 m above street level. With what velocity must the person throw the book so that it reaches the person in the window?

Join BYJU'S Learning Program

A window whose area is 2m2 opens on street where the street noise result in an intensity level at the window of 60db. How much acoustic power enters the window via sound waves ? Now, if an acoustic absorber is fitted at the window?

The correct option is D 2μWIntensity = 60 dB60 = 10 log (IIref)where Iref is the refrence intensity , general value of this is given by Iref=10−12wattm2I10−12 = anti log (6)I=10−12×antilog(6)=10−12×106=10−6Power = I× area = 2×10−6 watt

A window whose area is $2 m^{2}$ opens on street where the street noise result in an intensity level at the window of $60 d b$ . How much acoustic power enters the window via sound waves ? Now, if an acoustic absorber is fitted at the window?