A wire 1 m long has cross-section 1 mm2 and Y - 1-2-1011Pa- Find the work done in stretching it by 2 mm-

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Standard XII

Physics

Conductivity and Resistivity

A wire 1 m ...

Question

A wire $1 m$ long has cross-section $1 m m^{2}$ and $Y = 1.2 \times 10^{11} P a$ . Find the work done in stretching it by $2 m m .$

2.4J

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0.24J

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0.024J

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1.2J

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Solution

The correct option is A 0.24J
Work done in stretching is the potential energy stored which is given as
$U = \frac{1}{2} V Y ϵ^{2} = \frac{1}{2} (1 \times 10^{- 6}) \times (1.2 \times 10^{11}) \times (\frac{2 \times 10^{- 3}}{1})^{2} = 0.24 J$

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A wire 1m long has cross-section 1mm2 and Y=1.2×1011Pa. Find the work done in stretching it by 2mm.

The correct option is A 0.24JWork done in stretching is the potential energy stored which is given asU=12VYϵ2=12(1×10−6)×(1.2×1011)×(2×10−31)2=0.24J

A wire $1 m$ long has cross-section $1 m m^{2}$ and $Y = 1.2 \times 10^{11} P a$ . Find the work done in stretching it by $2 m m .$

The correct option is A 0.24J
Work done in stretching is the potential energy stored which is given as
$U = \frac{1}{2} V Y ϵ^{2} = \frac{1}{2} (1 \times 10^{- 6}) \times (1.2 \times 10^{11}) \times (\frac{2 \times 10^{- 3}}{1})^{2} = 0.24 J$