A wire 4 m long and 0.3 mm diameter is stretched by a force of 100N. If the extension in the wire is 0.3 mm, calculate the potential energy stored in the wire.

15J

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25 J

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15x10^-3J

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25x10^-3J

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Solution

The correct option is C
15x10^-3J

$U = \frac{1}{2} (s t r e s s) (s t r a i n) (v o l u m e)$

$= \frac{1}{2} \times (F o r c e) (e l o n g a t i o n)$

$= \frac{1}{2} \times 100 \times 3 \times 10^{- 4}$

$= 15 \times 10^{- 3}$ J

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A wire 4 m long and 0.3 mm diameter is stretched by a force of 100N. If the extension in the wire is 0.3 mm, calculate the potential energy stored in the wire.

The correct option is C 15x10-3J U=12 (stress) (strain) (volume) =12×(Force) (elongation) =12×100×3×10−4 =15×10−3J

The correct option is C
15x10^-3J

$U = \frac{1}{2} (s t r e s s) (s t r a i n) (v o l u m e)$

$= \frac{1}{2} \times (F o r c e) (e l o n g a t i o n)$

$= \frac{1}{2} \times 100 \times 3 \times 10^{- 4}$

$= 15 \times 10^{- 3}$ J