A wire ABCDEF is bent in the form as shown in figure. The wire carries a current I and is placed into a uniform magnetic field of induction B parallel to positive Y-axis. If each side is of length L, the force experienced by the wire will be :
A
IBL along the positive Z-direction
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B
IBL along the negative Z-direction
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C
2IBL along the positive Z-direction
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D
2IBL along the negative Z-direction
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Solution
The correct option is A IBL along the positive Z-direction Here we need to apply the Fleming's left hand rule to find force on a current carrying conductor in magnetic field.
Here we will consider each line segments separately.
For the segment
1. FE
F=iL×B=0
because here current is parallel to the magnetic field.
2. ED
F=−iLB^i
Force will be along negative x-axis
3. DC
F=iLB^k
Force will be along positive z-axis
4. CB
F=iLB^i
Force will be along positive x-axis
5. BA
F=iL×B=0
Force will be zero because the current is parallel to the magnetic field.
From above we can see that 2 and 4 will cancel out each other.