Question

A wire bent in the form of a square enclosed an area of 121 sq cm. If the same wire is
bent so as to form a circle, then find the area enclosed?

Answer 1

$Thesamelengthofwireisusedtoformasquare\&acircle.\therefore perimeterofthesquare=circumferenceofthecircle.......\left(i\right)Nowar.square=121{cm}^2.Sooneside=\sqrt{121{cm}^2.}=11cm.i.eperimeterofthesquare=11\times 4cm=44cm.........\left(ii\right)\therefore by\left(i\right),\left(ii\right)circumferenceofthecircle=44cm.⟹2\pi r=44whenristheradiusofthecircle\&\pi =\frac{22}{7}.⟹r=44\times \frac{7}{2\times 22}cm=7cm.\therefore ar.circle=\pi r^2=\frac{22}{7}\times 7^2{cm}^2=154{cm}^2.Ans-ar.circle=154{cm}^2.$