A wire carrying a current of 3 A is bent in the form of a parabola y2=4−x as shown in figure, where x and y are in metre.The wire is placed in a uniform magnetic field →B=5^k tesla.The force acting on the wire is
A
60^iN
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B
−60^iN
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C
30^iN
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D
−30^iN
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Solution
The correct option is D60^iN At x=0 y=±2m →FMNP=→FMP=i[→MP×B] =3[(4^j)×(5^k)] =60^i