A wire carrying a current of $4 A$ is in the form of a circle. It is necessary to have a magnetic field of induction $10^{- 6} T$ at the center. The radius is

2.51 m

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25.1 m

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251 m

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0.251 m

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Solution

The correct option is A $2.51 m$
$B = \frac{μ_{0} i}{2 r}$
$10^{- 6} = \frac{4 π \times 10^{- 7} \times 4}{2 \times r}$
$r = 2 \cdot 51 m$

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