A wire extends by 1 mm when a force is applied. What will be the elongation(in mm) in wire of same material if the force is doubled on the wire of same length and half the radius?
A
8
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B
4
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C
2
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D
1
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Solution
The correct option is A 8 a) say l= elongation; L= original length; Y= modulus of elasticity. Then from Hooke's law l=FLπr2Y=l∝Fr2 (Y and L are constant) l2l1=F2F1×(r1r2)2=2×(2)2=8⇒l2=8l1=8×1=8mm