A wire has a diameter of 0.2mm and a length of 50cm. The specific resistance of it's material is 40×10−6ohmcm. The current through it, when a potential difference of 2V is applied across it, is
A
3.14A
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B
31.4A
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C
0.314A
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D
0.0314A
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Solution
The correct option is C0.314A Given: l=50 cm, ρ=40×10−6Ωcm, r=0.1 mm =0.01 cm The resistance R is given by, R=ρlA=40×10−6×50π×(0.01)2≈6.37Ω Now the current through it when a potential difference of 2V is applied across it is: i=VR=26.37=0.314 A.