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Question

A wire has a diameter of 0.2mm and a length of 50cm. The specific resistance of it's material is 40×106ohmcm. The current through it, when a potential difference of 2V is applied across it, is

A
3.14A
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B
31.4A
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C
0.314A
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D
0.0314A
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Solution

The correct option is C 0.314A
Given: l=50 cm, ρ=40×106Ωcm, r=0.1 mm =0.01 cm
The resistance R is given by,
R=ρlA=40×106×50π×(0.01)26.37Ω
Now the current through it when a potential difference of 2V is applied across it is:
i=VR=26.37=0.314 A.

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