A wire has a diameter of 0.5 mm and a resistivity of 1.6 × $10^{- 6}$ ohm cm. How much of this wire would be required to make a 10 ohm coil?

1000 m

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112.7 m

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157.6 m

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57 m

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Solution

The correct option is B
112.7 m

D = 0.5 mm = 0.5 × $10^{- 3}$ m

ρ = 1.6 × $10^{- 6}$ ohm cm = 1.6 × $10^{- 8}$ ohm m

R = 10 ohm
Hence, l = 112.7 m

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A wire has a diameter of 0.5 mm and a resistivity of 1.6 × 10−6 ohm cm. How much of this wire would be required to make a 10 ohm coil?

The correct option is B 112.7 m D = 0.5 mm = 0.5 × 10−3 m ρ = 1.6 × 10−6 ohm cm = 1.6 × 10−8 ohm m R = 10 ohm Hence, l = 112.7 m

A wire has a diameter of 0.5 mm and a resistivity of 1.6 × $10^{- 6}$ ohm cm. How much of this wire would be required to make a 10 ohm coil?

The correct option is B
112.7 m

D = 0.5 mm = 0.5 × $10^{- 3}$ m

ρ = 1.6 × $10^{- 6}$ ohm cm = 1.6 × $10^{- 8}$ ohm m

R = 10 ohm
Hence, l = 112.7 m