A wire has a resistance 12Ω. It is bent in the form of a circle. The effective resistance between two point on any diameter is
A
6Ω
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B
3Ω
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C
12Ω
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D
24Ω
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Solution
The correct option is B3Ω Resistance of the wire of a semicircle =12/2=6Ω (as the length of semicircle wire is half of total length of wire and R∝l) There are two resistances 6Ω and 6Ωbetween two points on any diameter of the ring and they are in parallel. Thus, equivalent resistance is: Req=6×66+6=3Ω