Question

A wire has a resistance of $6\Omega$ . It is cut into two parts and both half value are connected in parallel the new resistance is

• A. 3 Ω
• B. 6 Ω
• C. 12 Ω
• D. 1.5 Ω

Answer 1

The correct option is D

1.5 Ω

$R=\frac{{\rho }^I}{A}-6\Omega$

When it is cut into two parts each resistance $R^1=\frac{6}{2}=3\Omega$

$R^{11}=\frac{R^1}{2}=\frac{3}{2}\Omega =1.5\Omega$