Question

A wire has a total length of 10 dm 10 cm. It is broken into 11 equal pieces. Finally, 3 such pieces are joined together end-to-end. Find the length of the joined wire (in dm).

• A. 3

Answer 1

The correct option is A 3
The initial length of the wire is 10 dm 10 cm.

We know,
1 dm = 10 cm
$\Rightarrow$ 10 dm = 100 cm

$\therefore$ 10 dm 10 cm = (100+10) cm = 110 cm

110 cm long wire is broken into 11 equal pieces.

Length of each piece $=\frac{\text{Total length of wire}}{\text{Total number of pieces}}$
$=\frac{110}{11}$ cm
$=10$ cm

Three small pieces are joined together end-to-end.


$\therefore$ Length of the joined wire $=10\text{cm}\times 3$
$=30\text{cm}$
$=\frac{30}{10}\text{dm}$
$=3\text{dm}$