A wire has frequency f. Its length is doubled by stretching. Its frequency now will be:
A
1.4f
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B
0.7f
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C
2f
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D
f
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Solution
The correct option is B0.7f Wehavef=12l√Tm∴f∝1landf∝1√mAndweknowthataslbecomesdoublemass/unitlengthbecomeshalf.∴fbecomes1√2timestheorignal.Hencef′=0.7f