A wire has resistance of $12 Ω$ . It is cut into two parts and both halve are connected in parallel. The new resistance is

3 Ω

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1.5 Ω

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12 Ω

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6 Ω

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Solution

The correct option is A $3 Ω$
As the wire is bent at its mid point, thus resistance of each segment $R = \frac{12}{2} = 6 Ω$
Both are in parallel
$∴$ Effective resistance between A and B $R^{'} = \frac{R_{1} \times R_{2}}{R_{1} + R_{2}} = \frac{6 \times 6}{6 + 6} = 3 Ω$

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A wire has resistance of 12Ω. It is cut into two parts and both halve are connected in parallel. The new resistance is

The correct option is A 3ΩAs the wire is bent at its mid point, thus resistance of each segment R=122=6ΩBoth are in parallel∴ Effective resistance between A and B R′=R1×R2R1+R2=6×66+6=3Ω

A wire has resistance of $12 Ω$ . It is cut into two parts and both halve are connected in parallel. The new resistance is

The correct option is A $3 Ω$
As the wire is bent at its mid point, thus resistance of each segment $R = \frac{12}{2} = 6 Ω$
Both are in parallel
$∴$ Effective resistance between A and B $R^{'} = \frac{R_{1} \times R_{2}}{R_{1} + R_{2}} = \frac{6 \times 6}{6 + 6} = 3 Ω$