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Question

A wire having a linear density 0.10kg/m is kept under a tension 490N it is observed that it resonates at a frequency of 400Hz and the next frequency 450Hz. The length of the wire is

A
14m
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B
0.7m
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C
1.6m
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D
0.49m
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Solution

The correct option is B 0.7m
Given-
T=490N
μ=0.1kg/m
f(n)=400Hz
f(n+1)=450Hz
Velocity of waves on string is given by-
v=(T/μ)
v=(490/0.1)
v=70m/s
Length of the wire cak be calculated by-
l=nλ1/2=(n+1)λ2/2
n×70/400=(n+1)×70/450
45n=40n+40
n=8
Substitute this in ,
l=8×70/(400×2)
l=0.7m
Therefore, length of the wire is 0.7m.
Hence,
option B is correct answer.

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