Question

A wire having mass per unit length $10$g/cm and density $800kg/m^3$ suspended rigid support. The stress in the wire if $10$kg-wt is attached to free its end is

Answer 1

A wire having mass per unit

length $=10g/cm$

density $=800kg/m^3$

which is suspended rigid support

The stress in the wire if $10kg-wt$ is attrached to free its end is

$800kg=1m^{3}10kg=\frac{10}{800}{m}^3\frac{1}{80}{m}^3\frac{10}{1000}kg=\frac{1}{100}m\therefore \frac{1}{100}kg=\frac{1}{100}m=\frac{\frac{1}{80}}{\frac{1}{100}}=\frac{100}{80}=\frac{5}{4}{m}^2$

$Stress=\frac{Force}{Area}=Pressure=\frac{\frac{1}{100}}{\frac{5}{4}}=\frac{4}{5}\times \frac{1}{100}=\frac{1}{100}N/m^2$