Question

A wire having resistance $12\Omega$ is bent in the form of an equilateral triangle. The effective resistance between any two corners of the triangle will be

• A. $6\Omega$
• B. $\frac{8}{3}\Omega$
• C. $9\Omega$
• D. $12\Omega$

Answer 1

The correct option is B $\frac{8}{3}\Omega$

As resistance, $R\propto length$
$\therefore$ Resistance of each arm $=\frac{12}{3}=4\Omega$
So, effective resistance between any two corners
$R_{eff}=\frac{4\times 8}{4+8}$
$=\frac{32}{12}=\frac{8}{3}\Omega$.