Question

A wire in a circular shape of radius 28 cm. If it is bent in the form of a square, what will be the area of the square formed?

Answer 1

It is given that the radius of the circle is 28 cm.

Length of the wire = Circumference of the circle
⇒ Circumference of the circle = $2\mathrm{\pi r}=\left(2\times \frac{22}{7}\times 28\right)$ cm = 176 cm
Let the wire be bent into the form of a square of side a cm.

Perimeter of the square = 176 cm

⇒ 4a = 176
⇒ a = $\left(\frac{176}{4}\right)$cm = 44 cm
Thus, each side of the square is 44 cm.

Area of the square = (Side)² = (a)² = (44 cm)²
= 1936 cm²
∴ Required area of the square formed = 1936 cm²