Question

A wire in the shape of an equilateral triangle with sides of length 1.00 m sits in a magnetic field of 2.00 T, pointing to the right. What is the magnitude of the magnetic flux through the triangle?

• A. 0 Wb
• B. 1.00 Wb
• C. 1.73 Wb
• D. 2.00 Wb
• E. 3.46 W

Answer 1

Answer: (A)

0 Wb

The magnetic flux $\varphi$ linked with a surface of area $A$ in a magnetic field $\overrightarrow{B}$ is given by ,

$\varphi =\overrightarrow{B}.\overrightarrow{A}=BA\cos \theta$ , where $\theta$ is the angle between $\overrightarrow{B}$ , and area vector $\overrightarrow{A}$ ,

in the given figure , the angle between magnetic field $\overrightarrow{B}$ and area vector $\overrightarrow{A}$ is ${90}^o$ , because area vector is taken perpendicular to the plane of area ,

therefore $\varphi =BA\cos {90}^0=0Wb$ (because $\cos 90=0$)