Question

A wire is bent in the form of a square of side $16.5cm$. It is straightened and then bent into a circle. What is the radius of the circle so formed ? $(Taken\pi =\frac{22}{7})$

Answer 1

Perimeter of wire would remain same

$\Rightarrow$ $4a=2\pi r$

$\Rightarrow$ $r=\frac{2a}{\pi }=\frac{2\times 16.5\times 7}{22}$

$=1.5\times 7$

$=10.5cm$