Question

A wire is bent into a rectangle of length 50 cm and breadth 30 cm. If the wire were straightened and then bent into a square, how many centimetres would each of its sides measure?

Answer 1

Given that a wire is bent into a rectangle of length 50 cm and breadth 30 cm.
The length of wire = perimeter of rectangle
= 2 (length + breadth)
= 2 (50 cm + 30 cm)
= 2 (80 cm)
= 160 cm
Next, the wire is straightened and then bent into a square.
The perimeter of the square will be equal to the length of wire.
Perimeter of square = 4 × side
⇒ 4 × side = 160 cm
⇒ side$=\frac{160\mathrm{cm}}{4}=40\mathrm{cm}$
Thus, the length of each side of square = 40 cm