Question

A wire is bent into the form of a square of side $27.5cm$. The wire is straightened and bent into the form of a circle. What will be the radius of the circle so formed?

Answer 1

Length of wire $=$ perimeter of the square
$$=(27.5\times 4)cm=110cm\text{.}$$
When the wire is bent into the form of a circle, then it represents the circumference of the circle which would be $110cm$.

Let $r$ be the radius of this circle
Then, circumference $=110cm$
we have $2\times \frac{22}{7}\times r\mid \because c=2\pi r$
$$\begin{array}{cc}\therefore \frac{44}{7}\times r& =110\\ \Rightarrow r& =\frac{110\times 7}{44}cm\\ & =17.5cm\end{array}$$