Question

Question 54

A wire is cut into several small pieces. Each of the small pieces is bent into a square of side 2 cm. If the total area of the small squares is 28 sq cm, what was the original length of the wire?

Answer 1

Given, side of square made by bending a small piece of wire = 2 cm

and total area of the small squares made by benting small pieces of wire = 28 sq cm

Now, number of small squares =$\frac{\text{Total area of small squares}}{\text{Area of one small squares}}$

= $\frac{28}{2\times 2}$

= $\frac{28}{4}$ = 7

Now, perimeter of a small square = 4 $\times$Side

= 4$\times$2

= 8 cm

Perimeter of 7 such small squares = Perimeter of one small square$\times$7

= 8$\times$7

= 56 cm

$\therefore$ Original length of wire = Perimeter of 7 small squares = 56 cm

Hence, the original length of wire is 56 cm.