A wire is stretched between two rigid supports vibrates in its fundamental mode with a frequency of 50Hz. The mass of the wire is 30g and its lines density is 4×10−2kgms−1. The speed of the transverse wave in the string is:
A
25ms−1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
50ms−1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
75ms−1
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
100ms−1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is C75ms−1 Here, mass of the wire, M=30g×10−3kg Mass per unit length of the wire,μ=4×10−2kgm−1 ∴ length of the wire, L=Mμ=30×10−3kg4×10−2kgm−1=0.75m For the fundamental mode, λ=2L=2×0.75m=1.5m Speed of the transverse wave, ν=υλ=(50s−1)(1.5m)=75ms−1