A wire is stretched to double its length. The strain is :

i n f i n i t y

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1

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z e r o

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0.5

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Solution

The correct option is D $1$
Longitudinal strain $= \frac{c h a n g e i n l e n g t h}{o r i g i n a l l e n g t h}$
If $l$ be the original length and if stretched to double of its length , change in length $= l$
So , strain $= 1$

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