Question

A wire is suspended by one end. At the other end a weight equivalent to 20 N force is applied. If the increase in length is 1.0 mm, the increase in energy of the wire will be

• A. 0.01 J
• B. 0.02 J
• C. 0.04 J
• D. 1.00 J

Answer 1

The correct option is A

0.01 J

Increase in energy =$\frac{1}{2}\times F\times △l$=$\frac{1}{2}\times 20\times 1\times {10}^{-3}=0.01J$