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Standard IX

Physics

Second Law of Motion

A wire is sus...

Question

A wire is suspended by one end. At the other end, a weight equivalent to 20 N force is applied. If the increase in length is I mm, then increase in the f the wire will be

0.01 J

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0.02 J

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0.04 J

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1.00 J

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Solution

The correct option is A 0.01 J
$P . E = \frac{1}{2} \times 20 \times 0.001 = 0.01 J$

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A wire is suspended by one end. At the other end, a weight equivalent to 20 N force is applied. If the increase in length is I mm, then increase in the f the wire will be

The correct option is A 0.01 JP.E=12×20×0.001=0.01J

The correct option is A 0.01 J
$P . E = \frac{1}{2} \times 20 \times 0.001 = 0.01 J$