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Byju's Answer

Standard XII

Physics

Stress-Strain Graph

A wire is sus...

Question

A wire is suspended from the ceiling and stretched under the action of a weight $F$ suspended from its other end. The force exerted by the ceiling on it is equal and opposite to the weight

Tensile stress at any cross section

A

of the wire is

\frac{F}{A}

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Tensile stress at any cross section is zero

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Tensile stress at any cross section

A

of the wire is

\frac{2 F}{A}

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Tension at any cross section

A

of the wire is

2 F

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Solution

The correct option is A Tensile stress at any cross section $A$ of the wire is $\frac{F}{A}$
From Above diagram,
Stress $σ = \frac{F o r c e}{A r e a} = \frac{F}{A}$
Option -A

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A 2m long light metal rod AB is suspended from the ceiling horizontally by means of two vertical wires of equal length tied to its ends. One wire is of brass and has cross section of $0.2 \times 10^{- 4} m^{2}$ and the other is of steel with $0.1 \times 10^{- 4} m^{2}$ cross section. In order to have equal stress in the two wires, a weight is hang from the rod. The position of the weight along the rod from end A should be.

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A wire is suspended from the ceiling and stretched under the action of a weight F suspended from its other end. The force exerted by the ceiling on it is equal and opposite to the weight

The correct option is A Tensile stress at any cross section A of the wire is FAFrom Above diagram,Stress σ=ForceArea=FAOption -A

A wire is suspended from the ceiling and stretched under the action of a weight $F$ suspended from its other end. The force exerted by the ceiling on it is equal and opposite to the weight

The correct option is A Tensile stress at any cross section $A$ of the wire is $\frac{F}{A}$
From Above diagram,
Stress $σ = \frac{F o r c e}{A r e a} = \frac{F}{A}$
Option -A