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Question

A wire is wound on a long rod of material of relative permeability μr=4000 to make a solenoid. If the current through the wire is 5 A and number of turns per unit length is 1000 per metre, then the magnetic field inside the solenoid is:

A
25.12 mT
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B
12.56 mT
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C
25.56 T
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D
25.12 T
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Solution

The correct option is D 25.12 T

Given that,
Relative permeability, μr=4000
Carried current, I=5 A
Number of turns, n=1000
therefore,
the magnetic intensity,
H=nI
H=1000×5=5000Am1
Now, the magnetic field inside the solenoid is
B=μH.....(i)
We know that,
μ=μ0μr=4π×107×4000

We get,
B=4π×107×4000×5000
B=25.12 T


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