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Question

A wire is wound on a long rod of material of relative permeability μr=4000 to make a solenoid. If the current through the wire is 5A and number of turns per length is 1000 per meter, then the magnetic field inside the solenoid is:

A
25.12 mT
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B
12.56 mT
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C
12.56 T
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D
25.12 T
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Solution

The correct option is D 25.12 T

Given that,

Relative permeability, μr=4000

Carried current, I=5A

Number of turns, n=1000

Therefore,

The magnetic intensity,

H=nI

H=1000×5

H=5000Am1

Now, the magnetic field inside the solenoid is

B=μH…. (I)

We know that,

μ=μ0μr

μ=4π×107×4000

Now put the value of μ in equation (I)

B=μH

B=4π×107×4000×5000

B=2×4π

B=8×3.14

B=25.12T

Hence the magnetic field inside the solenoid is B=25.12T.


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