Question

A wire 'LN' bent as shown in figure is placed in uniform perpendicular magnetic field of $5T$ .A $10A$ current flows through the wire.,Magnetic force experienced by the wire is:-

• A. $5N$
• B. $10N$
• C. $2.5N$
• D. $1.25N$

Answer 1

The correct option is A $5N$

$\begin{array}{c}{\overrightarrow{F}}_{net}=\left\{Bi{\left(\frac{4}{100}\right)}^2\right\}\hat{i}-\left\{Bi{\left(\frac{6}{100}\right)}^2\right\}\hat{j}\\ {\overrightarrow{F}}_{net}=\sqrt{{\left(\frac{86i}{100}\right)}^2+{\left(\frac{66i}{100}\right)}^2}\\ =\frac{6i}{100}\sqrt{8^2+6^2}\\ =\frac{Bi}{10}=\frac{5\times 10}{10}=5N\\ \therefore F_{net}=5N\end{array}$

Hence,

Option $A$ is correct answer.