A wire made of the material of Young's modulus $Y$ has an stress $S$ applied to it. If Poisson's ratio of the wire is $σ$ , the lateral strain is:

σ \frac{S}{Y}

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σ \frac{Y}{S}

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σ Y \times S

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\frac{S}{σ Y}

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Solution

The correct option is A $σ \frac{S}{Y}$
Longitudinal strain = $S / Y$ ;
Poisson's ratio is given as $\frac{L a t e r a l s t r a i n}{L o n g i t u d i n a l S t r a i n}$
$L a t e r a l S t r a i n = P o i s s o n^{'} s r a t i o \times L o n g i t u d i n a l S t r a i n = σ \frac{S}{Y}$

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