A wire of $10^{- 3} c m^{2}$ cross sectional area carries a current of 0.25 A, then current density is

$1.5 \times 10^{6} A m^{- 2}$

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$2.5 \times 10^{6} A m^{- 2}$

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$3.5 \times 10^{6} A m^{- 2}$

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$4.5 \times 10^{6} A m^{- 2}$

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Solution

The correct option is B
$2.5 \times 10^{6} A m^{- 2}$

$J = \frac{I}{A} = \frac{0.25}{10^{- 3} \times 10^{- 4}} = 2.5 \times 10^{6} A^{- 2}$

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Similar questions

A wire of $10^{- 3} c m^{2}$ cross sectional area carries a current of 0.25 A, then current density is

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