A wire of circular cross- section of diameter 1.0 mm is bent into a circular arc of radius 1.0 m by application of pure bending moments at its ends. The Young's modulus of the material of the wire is 100 GPa . The maximum tensile stress developed in the wire is _______ MPa.
50

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Solution

The correct option is A 50
Given ; E = 100 GPa, d= 1 mm, R = 1 m

$(σ_{b})_{m a x} = \frac{E Y_{m a x}}{R}$

$(σ_{b})_{m a x} = \frac{E \frac{d}{2}}{R} = \frac{100 \times 10^{3} \times 0.5}{1000} = 50 M P a$

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A wire of circular cross- section of diameter 1.0 mm is bent into a circular arc of radius 1.0 m by application of pure bending moments at its ends. The Young's modulus of the material of the wire is 100 GPa . The maximum tensile stress developed in the wire is _______ MPa.50

The correct option is A 50Given ; E = 100 GPa, d= 1 mm, R = 1 m (σb)max=EYmaxR (σb)max=Ed2R=100×103×0.51000=50MPa

A wire of circular cross- section of diameter 1.0 mm is bent into a circular arc of radius 1.0 m by application of pure bending moments at its ends. The Young's modulus of the material of the wire is 100 GPa . The maximum tensile stress developed in the wire is _______ MPa.
50

The correct option is A 50
Given ; E = 100 GPa, d= 1 mm, R = 1 m

$(σ_{b})_{m a x} = \frac{E Y_{m a x}}{R}$

$(σ_{b})_{m a x} = \frac{E \frac{d}{2}}{R} = \frac{100 \times 10^{3} \times 0.5}{1000} = 50 M P a$