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Question

A wire of infinite length carrying current of 10 A is placed along z axis (direction of current is along positive z - axis), then the magnetic field at a point (3,4,0) is

A
(3^i+4^j)×107 T
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B
(3.2^i+2.4^j)×107 T
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C
(4^i+4^j)×107 T
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D
(2.4^i+3.2^j)×107 T
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Solution

The correct option is B (3.2^i+2.4^j)×107 T

B=μ0i2πr=2×107×(10)5=4×107 T
B=Bcos θ(^i)+Bsin θ^j
=B{4^i5+3^j5}=B5{4^i+3^j}=4×1075{4^i+3^j}
=(3.2^i+2.4^j)×107 T

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