A wire of infinite length carrying current of 10 A is placed along z axis (direction of current is along positive z - axis), then the magnetic field at a point (3,4,0) is
A
(−3^i+4^j)×10−7 T
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B
(−3.2^i+2.4^j)×10−7 T
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C
(−4^i+4^j)×10−7 T
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D
(−2.4^i+3.2^j)×10−7 T
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Solution
The correct option is B(−3.2^i+2.4^j)×10−7 T
B=μ0i2πr=2×10−7×(10)5=4×10−7 T →B=Bcosθ(−^i)+Bsinθ^j =B{−4^i5+3^j5}=B5{−4^i+3^j}=4×10−75{−4^i+3^j} =(−3.2^i+2.4^j)×10−7 T