A wire of length 1m is stretched by a force of 10N. The area of cross-section of the wire is 2×10−6m2 and Young's modulus (Y) is 2×1011N/m2. Increase in length of the wire will be -
A
2.5×10−5cm
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B
2.5×10−5mm
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C
2.5×10−5m
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D
None of these
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Solution
The correct option is C2.5×10−5m As we know, Young's modulus (Y)=StressStrain=FAΔLL Stress=FA=10(2×10−6)=5×106N/m2 From Y=StressStrain 2×1011=5×106ΔLL ⇒ΔLL=2.5×10−5 ⇒ΔL=1×2.5×10−5 ⇒ΔL=2.5×10−5m